How Much Does Helium Weigh

2 Answers ii

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Most objects have densities that are very much larger than that of air. For calculating the motion of these objects in air, the buoyancy strength tin can exist neglected without introducing substantial errors. If you define "weight" every bit what a scale reads, though, it is technically not exactly $westward=mg$ unless the object is in a vacuum, but rather $w=mg-\rho g 5$, where$5$ is the book of the object and $\rho$ is the density of the surrounding fluid. For a helium ballon, this 2nd term (the buoyancy force) is not just non negligible, it is larger than the gravity force. So $w$ is negative.

answered November ane, 2018 at 1:32

Ben51Ben51

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$\begingroup$ why do people condense the buoyant force to just rho * k * 5? If the mass of the helium is substantial, albeit less than the second buoyant term, wouldn't you accept to lesson the buoyant force term past the mass of the helium x gravity? $\endgroup$

Nov ane, 2018 at 22:19
$\begingroup$ The mass of the helium plus the mass of the balloon is $chiliad$. The total gravitational force is $mg$. Neglecting buoyancy, that would exist the weight. The buoyancy force is actually the effect of higher air pressure near the lesser of the airship than well-nigh the summit, simply is most easily calculated by using Archimedes' principle, which says that it's equal to the weight of the displaced air. Does this make information technology clearer? $\endgroup$

Nov 1, 2018 at 22:40
$\begingroup$ It does assistance, thank you Ben51 you have actually cleared up a lot of headache for our visitor haha $\endgroup$

Nov two, 2018 at 1:12

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the helium balloon is experiencing a force in addition to that of gravity which you have non taken into account: the buoyant forcefulness caused past its being immersed in a medium that is more dumbo than it is.

answered Nov 1, 2018 at i:21